描述
现有某个商城部分订单数据,用户访问数据,如下所示:
订单信息表:order_tb(订单id-order_id,用户id-user_id,订单金额-order_price,订单创建时间-order_time)
order_id | user_id | order_price | order_time |
---|---|---|---|
101 | 11 | 380 | 2022-09-01 09:00:00 |
102 | 12 | 200 | 2022-09-01 10:00:00 |
103 | 13 | 260 | 2022-09-01 12:00:00 |
104 | 11 | 100 | 2022-09-02 11:00:00 |
105 | 12 | 150 | 2022-09-02 12:00:00 |
106 | 12 | 1200 | 2022-09-02 13:00:00 |
107 | 11 | 60 | 2022-09-03 09:00:00 |
108 | 13 | 380 | 2022-09-03 09:30:00 |
访问信息表:visit_tb(访问信息id-info_id,用户id-user_id,访问时间-visit_time,离开时间-leave_time)
info_id | user_id | visit_time | leave_time |
---|---|---|---|
911 | 10 | 2022-09-01 08:00:00 | 2022-09-01 09:02:00 |
912 | 11 | 2022-09-01 08:30:00 | 2022-09-01 09:10:00 |
913 | 12 | 2022-09-01 09:50:00 | 2022-09-01 10:12:00 |
914 | 13 | 2022-09-01 11:40:00 | 2022-09-01 12:22:00 |
921 | 11 | 2022-09-02 10:30:00 | 2022-09-02 11:05:00 |
922 | 11 | 2022-09-02 12:00:00 | 2022-09-02 12:02:00 |
923 | 12 | 2022-09-02 11:40:00 | 2022-09-02 13:15:00 |
924 | 13 | 2022-09-02 09:00:00 | 2022-09-02 09:02:00 |
925 | 14 | 2022-09-02 10:00:00 | 2022-09-02 10:40:00 |
931 | 10 | 2022-09-03 09:00:00 | 2022-09-03 09:22:00 |
932 | 11 | 2022-09-03 08:30:00 | 2022-09-03 09:10:00 |
933 | 13 | 2022-09-03 09:00:00 | 2022-09-03 09:32:00 |
请查询2022年9月2日这天下订单的用户的访问次数?
要求输出:user_id,访问次数
注:访问次数定义为用户在该日"访问-离开"则记录1次,输出结果按照访问次数降序排序
示例数据结果如下:
user_id | visit_nums |
---|---|
11 | 2 |
12 | 1 |
结果解释:
2022年9月2日这天user_id为11、12的用户下了订单,
其中11用户分别在10:30-11:05及12:00-12:02访问,故访问次数为2次,
12用户在11:40-13:15访问,故访问次数为1次。
示例1
输入:
drop table if exists `order_tb` ;
CREATE TABLE `order_tb` (
`order_id` int(11) NOT NULL,
`user_id` int(11) NOT NULL,
`order_price` int(11) NOT NULL,
`order_time` datetime NOT NULL,
PRIMARY KEY (`order_id`));
INSERT INTO order_tb VALUES(101,11,380,'2022-09-01 09:00:00');
INSERT INTO order_tb VALUES(102,12,200,'2022-09-01 10:00:00');
INSERT INTO order_tb VALUES(103,13,260,'2022-09-01 12:00:00');
INSERT INTO order_tb VALUES(104,11,100,'2022-09-02 11:00:00');
INSERT INTO order_tb VALUES(105,12,150,'2022-09-02 12:00:00');
INSERT INTO order_tb VALUES(106,12,1200,'2022-09-02 13:00:00');
INSERT INTO order_tb VALUES(107,11,60,'2022-09-03 09:00:00');
INSERT INTO order_tb VALUES(108,13,380,'2022-09-03 09:30:00');
drop table if exists `visit_tb` ;
CREATE TABLE `visit_tb` (
`info_id` int(11) NOT NULL,
`user_id` int(11) NOT NULL,
`visit_time` datetime NOT NULL,
`leave_time` datetime NOT NULL,
PRIMARY KEY (`info_id`));
INSERT INTO visit_tb VALUES(0911,10,'2022-09-01 08:00:00','2022-09-01 09:02:00');
INSERT INTO visit_tb VALUES(0912,11,'2022-09-01 08:30:00','2022-09-01 09:10:00');
INSERT INTO visit_tb VALUES(0913,12,'2022-09-01 09:50:00','2022-09-01 10:12:00');
INSERT INTO visit_tb VALUES(0914,13,'2022-09-01 11:40:00','2022-09-01 12:22:00');
INSERT INTO visit_tb VALUES(0921,11,'2022-09-02 10:30:00','2022-09-02 11:05:00');
INSERT INTO visit_tb VALUES(0922,11,'2022-09-02 12:00:00','2022-09-02 12:02:00');
INSERT INTO visit_tb VALUES(0923,12,'2022-09-02 11:40:00','2022-09-02 13:15:00');
INSERT INTO visit_tb VALUES(0924,13,'2022-09-02 09:00:00','2022-09-02 09:02:00');
INSERT INTO visit_tb VALUES(0925,14,'2022-09-02 10:00:00','2022-09-02 10:40:00');
INSERT INTO visit_tb VALUES(0931,10,'2022-09-03 09:00:00','2022-09-03 09:22:00');
INSERT INTO visit_tb VALUES(0932,11,'2022-09-03 08:30:00','2022-09-03 09:10:00');
INSERT INTO visit_tb VALUES(0933,13,'2022-09-03 09:00:00','2022-09-03 09:32:00');
输出:
user_id|visit_nums
11|2
12|1
答案
解法1:
select
user_id,
count(info_id) visit_nums
from
visit_tb
where
user_id in (
select user_id from order_tb where date(order_time)='2022-09-02'
)
and date(visit_time)='2022-09-02'
group by
user_id
order by visit_nums desc;
*本案例来自牛客网,但答案为原创,如有雷同纯属巧合*